Commit graph

8 commits

Author SHA1 Message Date
Andreas Herrmann
63823126c2 x86: memtest: add additional (regular) test patterns
Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:47 +01:00
Andreas Herrmann
bfb4dc0da4 x86: memtest: wipe out test pattern from memory
Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:46 +01:00
Andreas Herrmann
570c9e69aa x86: memtest: adapt log messages
- print test pattern instead of pattern number,
- show pattern as stored in memory,
- use proper priority flags,
- consistent use of u64 throughout the code

Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:46 +01:00
Andreas Herrmann
7dad169e57 x86: memtest: cleanup memtest function
Impact: code cleanup

Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:45 +01:00
Andreas Herrmann
6d74171bf7 x86: memtest: introduce array to select memtest patterns
Impact: code cleanup

Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:45 +01:00
Andreas Herrmann
40823f737e x86: memtest: reuse test patterns when memtest parameter exceeds number of available patterns
Impact: fix unexpected behaviour when pattern number is out of range

Current implementation provides 4 patterns for memtest. The code doesn't
check whether the memtest parameter value exceeds the maximum pattern number.

Instead the memtest code pretends to test with non-existing patterns, e.g.
when booting with memtest=10 I've observed the following

  ...
  early_memtest: pattern num 10
  0000001000 - 0000006000 pattern 0
  ...
  0000001000 - 0000006000 pattern 1
  ...
  0000001000 - 0000006000 pattern 2
  ...
  0000001000 - 0000006000 pattern 3
  ...
  0000001000 - 0000006000 pattern 4
  ...
  0000001000 - 0000006000 pattern 5
  ...
  0000001000 - 0000006000 pattern 6
  ...
  0000001000 - 0000006000 pattern 7
  ...
  0000001000 - 0000006000 pattern 8
  ...
  0000001000 - 0000006000 pattern 9
  ...

But in fact Linux didn't test anything for patterns > 4 as the default
case in memtest() is to leave the function.

I suggest to use the memtest parameter as the number of tests to be
performed and to re-iterate over all existing patterns.

Signed-off-by: Andreas Herrmann <andreas.herrmann3@amd.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2009-02-25 12:19:44 +01:00
Daniele Calore
2cb0ebeeb6 x86: memtest fix use of reserve_early()
Hi all,

Wrong usage of 2nd parameter in reserve_early call.
66/75: reserve_early(start_bad, last_bad - start_bad, "BAD RAM");
                                ^^^^^^^^^^^^^^^^^^^^

The correct way is to use 'end' address and not 'size'.
As a bonus a fix to the printk format.

Signed-off-by: Daniele Calore <orkaan@orkaan.org>
Acked-by: Yinghai Lu <yinghai@kernel.org>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2008-10-22 17:08:06 +02:00
Yinghai Lu
1f067167a8 x86: seperate memtest from init_64.c
it's separate functionality that deserves its own file.

This also prepares 32-bit memtest support.

Signed-off-by: Yinghai Lu <yhlu.kernel@gmail.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
2008-07-18 14:10:27 +02:00