sh: Remove implicit sign extension from assembler immediates

The SH instruction set has several instructions which accept an 8 bit
immediate operand. For logical instructions this operand is zero extended,
for arithmetic instructions the operand is sign extended. After adding an
option to the assembler to check this, it was found that several pieces
of assembly code were assuming this behaviour, and in one case
getting it wrong.

So this patch explicitly sign extends any immediate operands, which makes
it obvious what is happening, and fixes the one case which got it wrong.

Signed-off-by: Stuart Menefy <stuart.menefy@st.com>
Signed-off-by: Paul Mundt <lethal@linux-sh.org>

arch/sh/boot/compressed/head_32.S

@@ -22,7 +22,7 @@ startup:
 	bt	clear_bss
 	sub	r0, r2
 	mov.l	bss_start_addr, r0
-	mov	#0xe0, r1
+	mov	#0xffffffe0, r1
 	and	r1, r0			! align cache line
 	mov.l	text_start_addr, r3
 	mov	r0, r1

arch/sh/include/asm/entry-macros.S

@@ -7,7 +7,7 @@
 	.endm
 
 	.macro	sti
-	mov	#0xf0, r11
+	mov	#0xfffffff0, r11
 	extu.b	r11, r11
 	not	r11, r11
 	stc	sr, r10

arch/sh/kernel/cpu/sh3/entry.S

@@ -257,7 +257,7 @@ restore_all:
 	!
 	! Calculate new SR value
 	mov	k3, k2			! original SR value
-	mov	#0xf0, k1
+	mov	#0xfffffff0, k1
 	extu.b	k1, k1
 	not	k1, k1
 	and	k1, k2			! Mask original SR value

arch/sh/kernel/entry-common.S

@@ -98,8 +98,9 @@ need_resched:
 
 	mov	#OFF_SR, r0
 	mov.l	@(r0,r15), r0		! get status register
-	and	#0xf0, r0		! interrupts off (exception path)?
-	cmp/eq	#0xf0, r0
+	shlr	r0
+	and	#(0xf0>>1), r0		! interrupts off (exception path)?
+	cmp/eq	#(0xf0>>1), r0
 	bt	noresched
 	mov.l	3f, r0
 	jsr	@r0			! call preempt_schedule_irq

arch/sh/lib/clear_page.S

@@ -57,7 +57,7 @@ ENTRY(clear_page)
 ENTRY(__clear_user)
 	!
 	mov	#0, r0
-	mov	#0xe0, r1	! 0xffffffe0
+	mov	#0xffffffe0, r1
 	!
 	! r4..(r4+31)&~32 	   -------- not aligned	[ Area 0 ]
 	! (r4+31)&~32..(r4+r5)&~32 -------- aligned	[ Area 1 ]