of: alloc anywhere from memblock if range not specified

early_init_dt_alloc_reserved_memory_arch passes end as 0 to
__memblock_alloc_base, when limits are not specified. But
__memblock_alloc_base takes end value of 0 as MEMBLOCK_ALLOC_ACCESSIBLE
and limits the end to memblock.current_limit. This results in regions
never being placed in HIGHMEM area, for e.g. CMA.
Let __memblock_alloc_base allocate from anywhere in memory if limits are
not specified.

Acked-by: Marek Szyprowski <m.szyprowski@samsung.com>
Signed-off-by: Vinayak Menon <vinmenon@codeaurora.org>
Cc: stable@vger.kernel.org
Signed-off-by: Rob Herring <robh@kernel.org>
This commit is contained in:
Vinayak Menon 2016-02-22 19:15:44 +05:30 committed by Rob Herring
parent 6b22b3d161
commit e53b50c0cb

View file

@ -32,11 +32,13 @@ int __init __weak early_init_dt_alloc_reserved_memory_arch(phys_addr_t size,
phys_addr_t align, phys_addr_t start, phys_addr_t end, bool nomap,
phys_addr_t *res_base)
{
phys_addr_t base;
/*
* We use __memblock_alloc_base() because memblock_alloc_base()
* panic()s on allocation failure.
*/
phys_addr_t base = __memblock_alloc_base(size, align, end);
end = !end ? MEMBLOCK_ALLOC_ANYWHERE : end;
base = __memblock_alloc_base(size, align, end);
if (!base)
return -ENOMEM;