softlockup: ensure the task has been switched out once
When we check if a task has been switched out since the last scan, we might have a race condition on the following scenario: - the task is freshly created and scheduled - it puts its state to TASK_UNINTERRUPTIBLE and is not yet switched out - check_hung_task() scans this task and will report a false positive because t->nvcsw + t->nivcsw == t->last_switch_count == 0 Add a check for such cases. Signed-off-by: Frederic Weisbecker <fweisbec@gmail.com> Acked-by: Mandeep Singh Baines <msb@google.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
This commit is contained in:
parent
17406b82d6
commit
cf2592f59c
1 changed files with 7 additions and 1 deletions
|
@ -72,7 +72,13 @@ static void check_hung_task(struct task_struct *t, unsigned long timeout)
|
||||||
{
|
{
|
||||||
unsigned long switch_count = t->nvcsw + t->nivcsw;
|
unsigned long switch_count = t->nvcsw + t->nivcsw;
|
||||||
|
|
||||||
if (t->flags & PF_FROZEN)
|
/*
|
||||||
|
* Ensure the task is not frozen.
|
||||||
|
* Also, when a freshly created task is scheduled once, changes
|
||||||
|
* its state to TASK_UNINTERRUPTIBLE without having ever been
|
||||||
|
* switched out once, it musn't be checked.
|
||||||
|
*/
|
||||||
|
if (unlikely(t->flags & PF_FROZEN || !switch_count))
|
||||||
return;
|
return;
|
||||||
|
|
||||||
if (switch_count != t->last_switch_count) {
|
if (switch_count != t->last_switch_count) {
|
||||||
|
|
Loading…
Reference in a new issue