x86_64: oops_begin() fix
We don't want to see this: > BUG: using smp_processor_id() in preemptible [00000001] code: bash/3857 > caller is oops_begin+0xb/0x6f > > Call Trace: > [<ffffffff8020ab4d>] show_trace+0x34/0x4f > [<ffffffff8020ab7a>] dump_stack+0x12/0x17 > [<ffffffff8030d92d>] debug_smp_processor_id+0xad/0xbc > [<ffffffff8042388f>] oops_begin+0xb/0x6f > [<ffffffff8042520b>] do_page_fault+0x66a/0x7c0 > [<ffffffff804234bd>] error_exit+0x0/0x84 > coming out when the kernel is trying to oops. Cc: Andi Kleen <ak@suse.de> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -465,13 +465,14 @@ static unsigned int die_nest_count;
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unsigned __kprobes long oops_begin(void)
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{
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int cpu = smp_processor_id();
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int cpu;
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unsigned long flags;
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oops_enter();
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/* racy, but better than risking deadlock. */
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local_irq_save(flags);
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cpu = smp_processor_id();
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if (!spin_trylock(&die_lock)) {
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if (cpu == die_owner)
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/* nested oops. should stop eventually */;
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