x86_64: Always use builtin memcpy on gcc 4.3

Jan asked to always use the builtin memcpy on gcc 4.3 mainline because
it should generate better code than the old macro. Let's try it.

Cc: Jan Hubicka <jh@suse.cz>
Signed-off-by: Andi Kleen <ak@suse.de>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Andi Kleen 2007-07-21 17:09:58 +02:00 committed by Linus Torvalds
parent 5b74e3abb3
commit aac57f81eb

View file

@ -29,6 +29,9 @@ return (to);
function. */ function. */
#define __HAVE_ARCH_MEMCPY 1 #define __HAVE_ARCH_MEMCPY 1
#if (__GNUC__ == 4 && __GNUC_MINOR__ >= 3) || __GNUC__ > 4
extern void *memcpy(void *to, const void *from, size_t len);
#else
extern void *__memcpy(void *to, const void *from, size_t len); extern void *__memcpy(void *to, const void *from, size_t len);
#define memcpy(dst,src,len) \ #define memcpy(dst,src,len) \
({ size_t __len = (len); \ ({ size_t __len = (len); \
@ -38,7 +41,7 @@ extern void *__memcpy(void *to, const void *from, size_t len);
else \ else \
__ret = __builtin_memcpy((dst),(src),__len); \ __ret = __builtin_memcpy((dst),(src),__len); \
__ret; }) __ret; })
#endif
#define __HAVE_ARCH_MEMSET #define __HAVE_ARCH_MEMSET
void *memset(void *s, int c, size_t n); void *memset(void *s, int c, size_t n);