btrfs: use RCU in btrfs_show_devname for device list traversal
The show_devname callback is used to print device name in /proc/self/mounts, we need to traverse the device list consistently and read the name that's copied to a seq buffer so we don't need further locking. If the first device is being deleted at the same time, the RCU will allow us to read the device name, though it will become stale right after the RCU protection ends. This is unavoidable and the user can expect that the device will disappear from the filesystem's list at some point. The device_list_mutex was pretty heavy as it is used eg. for writing superblock and a few other IO related contexts. This can stall any application that reads the proc file for no reason. Reviewed-by: Anand Jain <anand.jain@oracle.com> Signed-off-by: David Sterba <dsterba@suse.com>
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1 changed files with 10 additions and 5 deletions
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@ -2304,11 +2304,18 @@ static int btrfs_show_devname(struct seq_file *m, struct dentry *root)
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struct list_head *head;
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struct rcu_string *name;
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mutex_lock(&fs_info->fs_devices->device_list_mutex);
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/*
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* Lightweight locking of the devices. We should not need
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* device_list_mutex here as we only read the device data and the list
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* is protected by RCU. Even if a device is deleted during the list
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* traversals, we'll get valid data, the freeing callback will wait at
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* least until until the rcu_read_unlock.
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*/
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rcu_read_lock();
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cur_devices = fs_info->fs_devices;
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while (cur_devices) {
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head = &cur_devices->devices;
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list_for_each_entry(dev, head, dev_list) {
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list_for_each_entry_rcu(dev, head, dev_list) {
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if (test_bit(BTRFS_DEV_STATE_MISSING, &dev->dev_state))
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continue;
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if (!dev->name)
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@ -2320,14 +2327,12 @@ static int btrfs_show_devname(struct seq_file *m, struct dentry *root)
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}
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if (first_dev) {
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rcu_read_lock();
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name = rcu_dereference(first_dev->name);
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seq_escape(m, name->str, " \t\n\\");
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rcu_read_unlock();
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} else {
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WARN_ON(1);
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}
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mutex_unlock(&fs_info->fs_devices->device_list_mutex);
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rcu_read_unlock();
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return 0;
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}
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