crypto: sha512 - Use binary and instead of modulus
The previous patch used the modulus operator over a power of 2 unnecessarily which may produce suboptimal binary code. This patch changes changes them to binary ands instead. Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
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1 changed files with 2 additions and 2 deletions
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@ -78,7 +78,7 @@ static inline void LOAD_OP(int I, u64 *W, const u8 *input)
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static inline void BLEND_OP(int I, u64 *W)
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static inline void BLEND_OP(int I, u64 *W)
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{
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{
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W[I % 16] += s1(W[(I-2) % 16]) + W[(I-7) % 16] + s0(W[(I-15) % 16]);
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W[I & 15] += s1(W[(I-2) & 15]) + W[(I-7) & 15] + s0(W[(I-15) & 15]);
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}
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}
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static void
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static void
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@ -105,7 +105,7 @@ sha512_transform(u64 *state, const u8 *input)
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#define SHA512_16_79(i, a, b, c, d, e, f, g, h) \
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#define SHA512_16_79(i, a, b, c, d, e, f, g, h) \
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BLEND_OP(i, W); \
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BLEND_OP(i, W); \
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t1 = h + e1(e) + Ch(e, f, g) + sha512_K[i] + W[(i)%16]; \
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t1 = h + e1(e) + Ch(e, f, g) + sha512_K[i] + W[(i)&15]; \
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t2 = e0(a) + Maj(a, b, c); \
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t2 = e0(a) + Maj(a, b, c); \
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d += t1; \
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d += t1; \
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h = t1 + t2
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h = t1 + t2
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