x86/ioapic.c: clean up replace_pin_at_irq_node logic and comments
There's no need for a control variable in replace_pin_at_irq_node(); it can just return if it finds the old apic/pin to replace. If the loop terminates, then it didn't find the old apic/pin, so it can add the new ones. Signed-off-by: Jeremy Fitzhardinge <jeremy.fitzhardinge@citrix.com>
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1 changed files with 5 additions and 8 deletions
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@ -512,25 +512,22 @@ static void add_pin_to_irq_node(struct irq_cfg *cfg, int node, int apic, int pin
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* Reroute an IRQ to a different pin.
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*/
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static void __init replace_pin_at_irq_node(struct irq_cfg *cfg, int node,
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int oldapic, int oldpin,
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int newapic, int newpin)
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int oldapic, int oldpin,
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int newapic, int newpin)
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{
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struct irq_pin_list *entry;
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int replaced = 0;
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for (entry = cfg->irq_2_pin; entry != NULL; entry = entry->next) {
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if (entry->apic == oldapic && entry->pin == oldpin) {
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entry->apic = newapic;
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entry->pin = newpin;
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replaced = 1;
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/* every one is different, right? */
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break;
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return;
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}
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}
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/* why? call replace before add? */
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if (!replaced)
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add_pin_to_irq_node(cfg, node, newapic, newpin);
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/* old apic/pin didn't exist, so just add new ones */
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add_pin_to_irq_node(cfg, node, newapic, newpin);
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}
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static void io_apic_modify_irq(struct irq_cfg *cfg,
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