include/linux/bitmap.h: turn bitmap_set and bitmap_clear into memset when possible
Several callers have constant 'start' and an 'nbits' that is a multiple of 8, so we can turn them into calls to memset. We don't need the entirety of 'start' and 'nbits' to be constant, we just need to know whether they're divisible by 8. Link: http://lkml.kernel.org/r/20170628153221.11322-4-willy@infradead.org Signed-off-by: Matthew Wilcox <mawilcox@microsoft.com> Acked-by: Rasmus Villemoes <linux@rasmusvillemoes.dk> Cc: Martin Schwidefsky <schwidefsky@de.ibm.com> Cc: Matthew Wilcox <willy@infradead.org> Signed-off-by: Andrew Morton <akpm@linux-foundation.org> Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
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@ -319,6 +319,9 @@ static __always_inline void bitmap_set(unsigned long *map, unsigned int start,
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{
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if (__builtin_constant_p(nbits) && nbits == 1)
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__set_bit(start, map);
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else if (__builtin_constant_p(start & 7) && IS_ALIGNED(start, 8) &&
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__builtin_constant_p(nbits & 7) && IS_ALIGNED(nbits, 8))
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memset((char *)map + start / 8, 0xff, nbits / 8);
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else
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__bitmap_set(map, start, nbits);
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}
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@ -328,6 +331,9 @@ static __always_inline void bitmap_clear(unsigned long *map, unsigned int start,
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{
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if (__builtin_constant_p(nbits) && nbits == 1)
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__clear_bit(start, map);
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else if (__builtin_constant_p(start & 7) && IS_ALIGNED(start, 8) &&
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__builtin_constant_p(nbits & 7) && IS_ALIGNED(nbits, 8))
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memset((char *)map + start / 8, 0, nbits / 8);
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else
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__bitmap_clear(map, start, nbits);
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}
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